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【江湖行源码】【java 优秀源码】【mysqlif函数源码】c 答题 源码_c语言答题系统

2024-12-23 01:34:11 来源:app打码源码

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2.求大神帮我写下这个C语言程序 把源代码回复给我 谢谢了!答答题

c 答题 源码_c语言答题系统

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       少年,题源江湖行源码作业是系统java 优秀源码用来回顾完善所学的知识的,而不是答答题mysqlif函数源码用来抄的。。题源怎么直行源码。系统wpa cli源码下面给出这个作业的答答题核心代码,仅供参考

       # include <stdio.h>

       # include <stdlib.h>

       # include <string.h>

       typedef struct student

       {

        char name[];

        int mathScore;

        int englishScore;

       }STU;

       void inputScore(STU * stu)

       {

       }

       int average(STU * stu)

       {

       }

       void sort(STU * stu)

       {

       }

       int main(void)

       {

        return 0;

       }

求大神帮我写下这个C语言程序 把源代码回复给我 谢谢了!题源

       /* determine the amount of the change

       change = (paid - check) * ;

        determine the number of dollars in the change

       dollars = change / ;

       …

       (1). Using the previous statements as a starting point,系统 write a C program

       that calculates the number of dollar bills( cents), quarters coins(

       cents), dimes coins ( cents), nickels coins (5 cents), and pennies coins (1

       cents) in the change when $ is used to pay a bill of $6..

       (2) Using the C program to calculate the change when a check of $.

       is paid using a $ bill.

       */

       #include "stdio.h"

       void getChange(int paid, float bill)

       {

        if (paid < bill)

        {

        printf("Your money cant paid for the bill!\n");

        return;

        }

        else

        {

        int remain;

        int dollor = 0,quarter = 0,dime = 0,nickel = 0,penny = 0;

        remain = (paid* - bill*)+0.5;

        dollor = remain/;

        printf("Change Dollors: %d\n",dollor);

        remain -= dollor*;

        quarter = remain/;

        printf("Change Quarters: %d\n",quarter);

        remain -= quarter*;

        dime = remain/;

        printf("Change Dimes: %d\n",dime);

        remain -= dime*;

        nickel = remain/5;

        printf("Change Nickels: %d\n",nickel);

        remain -=nickel*5;

        penny = remain;

        printf("Change Pennys: %d\n",penny);

        printf("Change finished!\n");

        }

       }

       void main()

       {

        int paid;

        float bill;

        printf("Please input your Paid($):");

        scanf("%d",&paid);

        printf("Please input your Bill($):");

        scanf("%f",&bill);

        printf("Your change is: \n");

        getChange(paid, bill);

       }