1.关于生日的源码c++程序源代码
2.用C语言写的计算器源代码
3.用C++编写的小游戏源代码
关于生日的c++程序源代码
#include <stdio.h>
int main()
{
printf("XXX 生日快乐！\n");
return 0;
}
请使用tc或ANSI C兼容编译器编译，源码并请在dos提示符下运行此程序，源码谢谢合作！源码
用C语言写的源码数据中心可视化监控源码计算器源代码
#include<stdio.h>
#include<iostream.h>
#include<stdlib.h>
#include<string.h>
#include<ctype.h>
typedef float DataType;
typedef struct
{
DataType *data;
int max;
int top;
}Stack;
void SetStack(Stack *S,int n)
{
S->data=(DataType*)malloc(n*sizeof(DataType));
if(S->data==NULL)
{
printf("overflow");
exit(1);
}
S->max=n;
S->top=-1;
}
void FreeStack(Stack *S)
{
free(S->data);
}
int StackEmpty(Stack *S)
{
if(S->top==-1)
return(1);
return(0);
}
DataType Peek(Stack *S)
{
if(S->top==S->max-1)
{
printf("Stack is empty!\n");
exit(1);
}
return(S->data[S->top]);
}
void Push(Stack *S,DataType item)
{
if(S->top==S->max-1)
{
printf("Stack is full!\n");
exit(1);
}
S->top++;
S->data[S->top]=item;
}
DataType Pop(Stack *S)
{
if(S->top==-1)
{
printf("Pop an empty stack!\n");
exit(1);
}
S->top--;
return(S->data[S->top+1]);
}
typedef struct
{
char op;
int inputprecedence;
int stackprecedence;
}DataType1;
typedef struct
{
DataType1 *data;
int max;
int top;
}Stack1;
void SetStack1(Stack1 *S,int n)
{
S->data=(DataType1*)malloc(n*sizeof(DataType1));
if(S->data==NULL)
{
printf("overflow");
exit(1);
}
S->max=n;
S->top=-1;
}
void FreeStack1(Stack1 *S)
{
free(S->data);
}
int StackEmpty1(Stack1 *S)
{
if(S->top==-1)
return(1);
return(0);
}
DataType1 Peek1(Stack1 *S)
{
if(S->top==S->max-1)
{
printf("Stack1 is empty!\n");
exit(1);
}
return(S->data[S->top]);
}
void Push1(Stack1 *S,DataType1 item)
{
if(S->top==S->max-1)
{
printf("Stack is full!\n");
exit(1);
}
S->top++;
S->data[S->top]=item;
}
DataType1 Pop1(Stack1 *S)
{
if(S->top==-1)
{
printf("Pop an empty stack!\n");
exit(1);
}
S->top--;
return(S->data[S->top+1]);
}
DataType1 MathOptr(char ch)
{
DataType1 optr;
optr.op=ch;
switch(optr.op)
{
case'+':
case'-':
optr.inputprecedence=1;
optr.stackprecedence=1;
break;
case'*':
case'/':
optr.inputprecedence=2;
optr.stackprecedence=2;
break;
case'(':
optr.inputprecedence=3;
optr.stackprecedence=-1;
break;
case')':
optr.inputprecedence=0;
optr.stackprecedence=0;
break;
}
return(optr);
}
void Evaluate(Stack *OpndStack,DataType1 optr)
{
DataType opnd1,opnd2;
opnd1=Pop(OpndStack);
opnd2=Pop(OpndStack);
switch(optr.op)
{
case'+':
Push(OpndStack,opnd2+opnd1);
break;
case'-':
Push(OpndStack,opnd2-opnd1);
break;
case'*':
Push(OpndStack,opnd2*opnd1);
break;
case'/':
Push(OpndStack,opnd2/opnd1);
break;
}
}
int isoptr(char ch)
{
if(ch=='+'||ch=='-'||ch=='*'||ch=='/'||ch=='(')
return(1);
return(0);
}
void Infix(char *str)
{
int i,k,n=strlen(str);
char ch,numstr[];
DataType opnd;
DataType1 optr;
Stack OpndStack;
Stack1 OptrStack;
SetStack(&OpndStack,n);
SetStack1(&OptrStack,n);
k=0;
ch=str[k];
while(ch!='=')
if(isdigit(ch)||ch=='.')
{
for(i=0;isdigit(ch)||ch=='.';i++)
{
numstr[i]=ch;
k++;
ch=str[k];
}
numstr[i]='\0';
opnd= atof(numstr);
Push(&OpndStack,opnd);
}
else
if(isoptr(ch))
{
optr=MathOptr(ch);
while(Peek1(&OptrStack).stackprecedence>=optr.inputprecedence)
Evaluate(&OpndStack,Pop1(&OptrStack));
Push1(&OptrStack,optr);
k++;
ch=str[k];
}
else if(ch==')')
{
optr=MathOptr(ch);
while(Peek1(&OptrStack).stackprecedence>=optr.inputprecedence)
Evaluate(&OpndStack,Pop1(&OptrStack));
Pop1(&OptrStack);
k++;
ch=str[k];
}
while(!StackEmpty1(&OptrStack))
Evaluate(&OpndStack,Pop1(&OptrStack));
opnd=Pop(&OpndStack);
cout<<"你输入表达式的计算结果为"<<endl;
printf("%-6.2f\n",opnd);
FreeStack(&OpndStack);
FreeStack1(&OptrStack);
}
void main()
{
cout<<"请输入你要计算的表达式,并以“=”号结束。"<<endl;
char str[];
gets(str);
Infix(str);
=================================================================
哈哈！源码buff_call源码给分吧！源码
用C++编写的源码小游戏源代码
五子棋的代码：#include<iostream>
#include<stdio.h>
#include<stdlib.h>
#include <time.h>
using namespace std;
const int N=; //*的棋盘
const char ChessBoardflag = ' '; //棋盘标志
const char flag1='o'; //玩家1或电脑的棋子标志
const char flag2='X'; //玩家2的棋子标志
typedef struct Coordinate //坐标类
{
int x; //代表行
int y; //代表列
}Coordinate;
class GoBang //五子棋类
{
public:
GoBang() //初始化
{
InitChessBoard();
}
void Play() //下棋
{
Coordinate Pos1; // 玩家1或电脑
Coordinate Pos2; //玩家2
int n = 0;
while (1)
{
int mode = ChoiceMode();
while (1)
{
if (mode == 1) //电脑vs玩家
{
ComputerChess(Pos1,flag1); // 电脑下棋
if (GetVictory(Pos1, 0, flag1) == 1) //0表示电脑,真表示获胜
break;
PlayChess(Pos2, 2, flag2); //玩家2下棋
if (GetVictory(Pos2, 2, flag2)) //2表示玩家2
break;
}
else //玩家1vs玩家2
{
PlayChess(Pos1, 1, flag1); // 玩家1下棋
if (GetVictory(Pos1, 1, flag1)) //1表示玩家1
break;
PlayChess(Pos2, 2, flag2); //玩家2下棋
if (GetVictory(Pos2, 2, flag2)) //2表示玩家2
break;
}
}
cout << "***再来一局***" << endl;
cout << "y or n :";
char c = 'y';
cin >> c;
if (c == 'n')
break;
}
}
protected:
int ChoiceMode() //选择模式
{
int i = 0;
system("cls"); //系统调用，清屏
InitChessBoard(); //重新初始化棋盘
cout << "***0、源码退出 1、源码电脑vs玩家 2、源码玩家vs玩家***" << endl;
while (1)
{
cout << "请选择：";
cin >> i;
if (i == 0) //选择0退出
exit(1);
if (i == 1 || i == 2)
return i;
cout << "输入不合法" << endl;
}
}
void InitChessBoard() //初始化棋盘
{
for (int i = 0; i < N + 1; ++i)
{
for (int j = 0; j < N + 1; ++j)
{
_ChessBoard[i][j] = ChessBoardflag;
}
}
}
void PrintChessBoard() //打印棋盘，源码这个函数可以自己调整
{
system("cls"); //系统调用，源码无限法则透视源码清空屏幕
for (int i = 0; i < N+1; ++i)
{
for (int j = 0; j < N+1; ++j)
{
if (i == 0) //打印列数字
{
if (j!=0)
printf("%d ",源码 j);
else
printf(" ");
}
else if (j == 0) //打印行数字
printf("%2d ", i);
else
{
if (i < N+1)
{
printf("%c |",_ChessBoard[i][j]);
}
}
}
cout << endl;
cout << " ";
for (int m = 0; m < N; m++)
{
printf("--|");
}
cout << endl;
}
}
void PlayChess(Coordinate& pos, int player, int flag) //玩家下棋
{
PrintChessBoard(); //打印棋盘
while (1)
{
printf("玩家%d输入坐标：", player);
cin >> pos.x >> pos.y;
if (JudgeValue(pos) == 1) //坐标合法
break;
cout << "坐标不合法，重新输入" << endl;
}
_ChessBoard[pos.x][pos.y] = flag;
}
void ComputerChess(Coordinate& pos,源码 char flag) //电脑下棋
{
PrintChessBoard(); //打印棋盘
int x = 0;
int y = 0;
while (1)
{
x = (rand() % N) + 1; //产生1~N的随机数
srand((unsigned int) time(NULL));
y = (rand() % N) + 1; //产生1~N的随机数
srand((unsigned int) time(NULL));
if (_ChessBoard[x][y] == ChessBoardflag) //如果这个位置是空的，也就是没有棋子
break;
}
pos.x = x;
pos.y = y;
_ChessBoard[pos.x][pos.y] = flag;
}
int JudgeValue(const Coordinate& pos) //判断输入坐标是不是合法
{
if (pos.x > 0 && pos.x <= N&&pos.y > 0 && pos.y <= N)
{
if (_ChessBoard[pos.x][pos.y] == ChessBoardflag)
{
return 1; //合法
}
}
return 0; //非法
}
int JudgeVictory(Coordinate pos, char flag) //判断有没有人胜负(底层判断)
{
int begin = 0;
int end = 0;
int begin1 = 0;
int end1 = 0;
//判断行是否满足条件
(pos.y - 4) > 0 ? begin = (pos.y - 4) : begin = 1;
(pos.y + 4) >N ? end = N : end = (pos.y + 4);
for (int i = pos.x, j = begin; j + 4 <= end; j++)
{
if (_ChessBoard[i][j] == flag&&_ChessBoard[i][j + 1] == flag&&
_ChessBoard[i][j + 2] == flag&&_ChessBoard[i][j + 3] == flag&&
_ChessBoard[i][j + 4] == flag)
return 1;
}
//判断列是否满足条件
(pos.x - 4) > 0 ? begin = (pos.x - 4) : begin = 1;
(pos.x + 4) > N ? end = N : end = (pos.x + 4);
for (int j = pos.y, i = begin; i + 4 <= end; i++)
{
if (_ChessBoard[i][j] == flag&&_ChessBoard[i + 1][j] == flag&&
_ChessBoard[i + 2][j] == flag&&_ChessBoard[i + 3][j] == flag&&
_ChessBoard[i + 4][j] == flag)
return 1;
}
int len = 0;
//判断主对角线是否满足条件
pos.x > pos.y ? len = pos.y - 1 : len = pos.x - 1;
if (len > 4)
len = 4;
begin = pos.x - len; //横坐标的起始位置
begin1 = pos.y - len; //纵坐标的起始位置
pos.x > pos.y ? len = (N - pos.x) : len = (N - pos.y);
if (len>4)
len = 4;
end = pos.x + len; //横坐标的结束位置
end1 = pos.y + len; //纵坐标的结束位置
for (int i = begin, j = begin1; (i + 4 <= end) && (j + 4 <= end1); ++i, ++j)
{
if (_ChessBoard[i][j] == flag&&_ChessBoard[i + 1][j + 1] == flag&&
_ChessBoard[i + 2][j + 2] == flag&&_ChessBoard[i + 3][j + 3] == flag&&
_ChessBoard[i + 4][j + 4] == flag)
return 1;
}
//判断副对角线是否满足条件
(pos.x - 1) >(N - pos.y) ? len = (N - pos.y) : len = pos.x - 1;
if (len > 4)
len = 4;
begin = pos.x - len; //横坐标的起始位置
begin1 = pos.y + len; //纵坐标的起始位置
(N - pos.x) > (pos.y - 1) ? len = (pos.y - 1) : len = (N - pos.x);
if (len>4)
len = 4;
end = pos.x + len; //横坐标的结束位置
end1 = pos.y - len; //纵坐标的结束位置
for (int i = begin, j = begin1; (i + 4 <= end) && (j - 4 >= end1); ++i, --j)
{
if (_ChessBoard[i][j] == flag&&_ChessBoard[i + 1][j - 1] == flag&&
_ChessBoard[i + 2][j - 2] == flag&&_ChessBoard[i + 3][j - 3] == flag&&
_ChessBoard[i + 4][j - 4] == flag)
return 1;
}
for (int i = 1; i < N + 1; ++i) //棋盘有没有下满
{
for (int j =1; j < N + 1; ++j)
{
if (_ChessBoard[i][j] == ChessBoardflag)
return 0; //0表示棋盘没满
}
}
return -1; //和棋
}
bool GetVictory(Coordinate& pos, int player, int flag) //对JudgeVictory的一层封装，得到具体那个玩家获胜
{
int n = JudgeVictory(pos,负13的源码 flag); //判断有没有人获胜
if (n != 0) //有人获胜，0表示没有人获胜
{
PrintChessBoard();
if (n == 1) //有玩家赢棋
{
if (player == 0) //0表示电脑获胜，1表示玩家1,2表示玩家2
printf("***电脑获胜***\n");
else
printf("***恭喜玩家%d获胜***\n", player);
}
else
printf("***双方和棋***\n");
return true; //已经有人获胜
}
return false; //没有人获胜
}
private:
char _ChessBoard[N+1][N+1];
};
扩展资料：
设计思路
1、进行问题分析与设计，计划实现的海地易支付源码功能为，开局选择人机或双人对战，确定之后比赛开始。
2、比赛结束后初始化棋盘，询问是否继续比赛或退出，后续可加入复盘、悔棋等功能。
3、整个过程中，涉及到了棋子和棋盘两种对象，同时要加上人机对弈时的AI对象，即涉及到三个对象。
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