1.JavaScript之reduce()的解源解器用法
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JavaScript之reduce()的用法
首先,参考了这位大佬的码源码破总结,敲了一遍,解源解器收获很大。码源码破seo源码教程视频记录下来。解源解器参考链接背景:之前是码源码破接触vue源码的时候,发现使用reduce的解源解器地方很多。当时也是码源码破在看别人分享,简单带过,解源解器发现很好用。码源码破简单研究后,解源解器通达信分时图源码很少用到。码源码破导致理解不深。解源解器今天碰到到使用场景,码源码破特意花时间研究了一番,解源解器可以说理解的qt5开发及实例源码很到位了。
语法arr.reduce(function(prev,cur,index,arr){ ...},init);其中,\arr表示原数组;\prev表示上一次调用回调时的返回值,或者初始值init;\cur表示当前正在处理的数组元素;\index表示当前正在处理的数组元素的索引,若提供init值,则索引为0,二维码 登录 源码否则索引为1;\init表示初始值。这个初始值在很多技巧上要用到,要重点留意
在实际使用当中,其实常用的参数只有两个:prev和cur。结合例子来分析一番。冒险岛服务端源码
实例以下举的例子除了用reduce来实现,还有很多其他的方法。不过使用reduce有它独有的技巧性和方便。
1、求数组的和方式一:
letarr=[3,4,5,6,9,2,4,6];letsum=arr.reduce((pre,cur,index,arr)=>{ //console.log('index:',index);//console.log('arr:',arr);returnpre+cur;})console.log(sum);方式二:
letsum=arr.reduce((pre,cur,index,arr)=>{ //console.log('index:',index);//console.log('arr:',arr);returnpre+cur;},0)console.log(sum);注意:方式二,由于传入了初始值0,所以pre的初始值就是0,cur的值,就是数组的第一个值为3;如果不传初始值的话,就如方式一,这时,pre的值是3,cur的值是4;相加后为7,作为下一轮的pre的值,cur是5,依次类推下去。
2、求数组的最大值方式一:
letarr=[1,4,5,6,9,2,4,6];letmax=arr.reduce((pre,cur)=>{ returnMath.max(pre,cur)})console.log(max);方式二:
letmax2=arr.reduce((pre,cur)=>{ returnpre>cur?pre:cur;})console.log('max2:',max2);3、给数组去重letnewArr=arr.reduce((pre,cur)=>{ pre.indexOf(cur)===-1&&pre.push(cur)returnpre},[])console.log(newArr);进阶用法1.求字符串中字幕出现的次数conststr='sfhjasfjgfasjuwqrqadqeiqsajsdaiwqdaklldflas-cmxzmnha';constres=str.split('').reduce((pre,cur)=>{ pre[cur]?pre[cur]++:pre[cur]=1;returnpre},{ })console.log('汇总次数:',res);2.数组转数组letarr1=[2,3,4,5,6,7];letnewArr1=arr1.reduce((pre,cur)=>{ pre.push(cur*cur)returnpre;},[])console.log('数组转数组:',newArr1);3.数组转对象letstreams=[{ name:'博士',id:1},{ name:'硕士',id:2},{ name:'本科',id:3}];letobj1=streams.reduce((pre,cur)=>{ pre[cur.id]=cur;returnpre;},{ })console.log('数组转对象:',obj1);高级用法1.多维的叠加执行操作例子:各科成绩占比不一样,求结果
constresult=[{ subject:'math',score:},{ subject:'chinese',score:},{ subject:'english',score:},];constdis={ math:0.5,chinese:0.2,english:0.4};letres2=result.reduce((pre,cur)=>{ returndis[cur.subject]*cur.score+pre},0)console.log('多维叠加:',res2);加大难度:商品对应不同国家汇率不同,求价格
letarr=[3,4,5,6,9,2,4,6];letsum=arr.reduce((pre,cur,index,arr)=>{ //console.log('index:',index);//console.log('arr:',arr);returnpre+cur;})console.log(sum);、扁平一个二维数组letarr=[3,4,5,6,9,2,4,6];letsum=arr.reduce((pre,cur,index,arr)=>{ //console.log('index:',index);//console.log('arr:',arr);returnpre+cur;})console.log(sum);1多维数组扁平化
3、对象数组去重letarr=[3,4,5,6,9,2,4,6];letsum=arr.reduce((pre,cur,index,arr)=>{ //console.log('index:',index);//console.log('arr:',arr);returnpre+cur;})console.log(sum);、compose函数reduxcompose源码实现
letarr=[3,4,5,6,9,2,4,6];letsum=arr.reduce((pre,cur,index,arr)=>{ //console.log('index:',index);//console.log('arr:',arr);returnpre+cur;})console.log(sum);3å¦ä½å¨ç³»ç»å®è£ ARGB
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